Euler's proof concerning ( [Maple Math] ).

Suppose [Maple Math] (mod p ) for some prime p with [Maple Math] (mod 4). Then from [Maple Math] (mod p ) one has [Maple Math] (mod p ), giving

[Maple Math] (mod p ) ... (i)

But clearly [Maple Math] (mod p), and so by Fermat's little theorem

[Maple Math] (mod p ) ... (ii)

and (i) and (ii) are incompatible for odd p , since they imply [Maple Math] (mod p ).

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This page was last updated 18 February 2005 15:08:43 -0000